Manu and Jade are at the "Maths End" amusement park. They go on two different Ferris wheels at the same time ($t=0$).
1. The Kiddy-Wheel (Jade):
2. The Flying-High (Manu):
The Problem: Due to trees, Jade can only see Manu when:
Achievement: Form a trigonometric model for ONE wheel (Jade OR Manu). Define variables correctly.
Merit: Form correct models for BOTH wheels and use them to find a simple value (e.g., height at $t=10$).
Excellence: Form a generalisation or chain of reasoning. Find the time intervals where they can see each other (solving simultaneous inequalities).
Since Jade starts at the bottom, a $- \cos$ curve is the smartest choice (no horizontal shift $C$).
Form: $h_J(t) = -A \cos(Bt) + D$
Enter: $y = -3.75\cos(0.209x) + 4.25$
Manu starts at the mid-point going up. This is exactly what a $+\sin$ curve does!
Form: $h_M(t) = A \sin(Bt) + D$
Enter: $y = 20\sin(0.157x) + 23$
To get E7/E8, you must:
Instructions:
Note: The graph shows the first 130 seconds so you can see the repeating pattern.
Why are there multiple answers?
The "Pattern" of Visibility:
Within every 120s cycle, there are four opportunities:
Conclusion: To answer the "Long Term Trend" question, you pick one of these and say it repeats every $120k$ seconds.